Rublev d. Seyboth Wild

Rublev beat Seyboth Wild 7-5, 6-4, 3-6, 4-6, 7-6(6) in the first round at the Australian Open - Melbourne. Rublev won 185 of 356 points (52%). Rublev hit 21 aces to 15 and won 83% of points behind the first serve (83/100) against 70% for Seyboth Wild. Rublev converted 4 of 23 break points and saved 4 of 8 faced; Seyboth Wild converted 4 of 8. Seyboth Wild double-faulted 6 times. Winners to unforced errors: 88–40 for Rublev, 68–45 for Seyboth Wild. The match was played on hard in Australia.